Oppermann’s Theorem

Fred Daniel Kline

2 August 2011 --- Copyright © 2011

L. H. F. Oppermann conjectured that when n is a whole number >1, at least one prime number lies between n(n-1) and index_1.gif and also between index_2.gif and n(n+1).  By modifying Paul Erdős’ proof of the Sylvester-Schur Theorem, we show that one or more primes lie within [ Φ(n-1),   Φ(n) ) where Φ(n) returns an Oppermann boundary point (which we define as a semipronic number.)

Preliminaries

Landau’s Problems

From Wikipedia, the free encyclopedia [1]

At the 1912 International Congress of Mathematicians, Edmund Landau listed four basic problems about primes. These problems were characterised in his speech as “unattackable at the present state of science” and are now known as Landau’s problems. They are as follows:

   1. Goldbach’s conjecture: Can every even integer greater than 2 be written as the sum of two primes?
   2. Twin prime conjecture: Are there infinitely many primes p such that p + 2 is prime?
   3. Legendre’s conjecture: Does there always exist at least one prime between consecutive perfect squares?
   4. Are there infinitely many primes p such that p − 1 is a perfect square? In other words: Are there infinitely many primes of the form n^2 + 1?

We suggest that 3. Legendre’s conjecture would have been 3. Oppermann’s conjecture had Edmund Landau been aware of it at the time.  Oppermann’s conjecture is the stronger of the two.

Oppermann’s Conjecture

From the Overview of the Royal Danish Sciences Institution’s work and its members’ work in the year 1882. [2] [3]

Oppermann, L. H. F., Professor, Lecturer in German at the University of Copenhagen; Knight of Dannebrog (Denmark) April 16th 1875.

In the notes from a meeting on March 9th 1877, after discussing papers by Legendre, J. W. L. Glaisher, and Meissel,  Oppermann stated:

At the same occasion, I made people aware of the not yet proven conjecture, that when n is a whole number >1, at least one prime number lies between n(n-1) and index_3.gif and also between index_4.gif and n(n+1).

Danish-to-English translation by Jesper Madsen.

A Useful Function

The capital Phi function returns the semipronic number for the n th step, for all n > 0

index_5.gif

Definitions

pronic numbers [4]

Pronic (or oblong) numbers are the products of two consecutive numbers, a × (a+1) for all a > 0

It is easy to see that index_6.gif  and index_7.gif

semipronic numbers

Semipronic is the term we use to describe the Oppermann boundary points, which are the numbers in the set of perfect squares interleaved with the pronic numbers.[5]

For the perfect squares, it is easy to see that index_8.gif  and index_9.gif which leads us to these  four equalities:

index_10.gif

index_11.gif

index_12.gif

index_13.gif

which we simplify by using the capital Phi function:

index_14.gif

index_15.gif

index_16.gif

index_17.gif

index_18.gif

index_19.gif

index_20.gif

index_21.gif

index_22.gif

Theorem

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